If binding energy of hypothetical nuclei P,Q and R are 112MeV,106MeV and 230MeV respectively, then the energy released in the reaction P+Q arrow R is

Question

If binding energy of hypothetical nuclei P,Q and R are 112MeV,106MeV and 230MeV respectively, then the energy released in the reaction P+Q arrow R is (A) 2MeV (B) 12MeV (C) 241MeV (D) 22MeV

Tardigrade Admin · Accepted Answer

From the given reaction, P+Q arrow R The binding energy is the difference of energies between reactant and product, ⇒ 230-(.112+106.)=12MeV

Q. If binding energy of hypothetical nuclei $P, Q$ and $R$ are $112 M e V, 106 M e V$ and $230 M e V$ respectively, then the energy released in the reaction $P + Q \to R$ is

$2 M e V$

$12 M e V$

$241 M e V$

$22 M e V$

From the given reaction,
$P + Q \to R$
The binding energy is the difference of energies between reactant and product,
$\Rightarrow 230 - (112 + 106) = 12 M e V$

Q. If binding energy of hypothetical nuclei P,Q and R are 112MeV,106MeV and 230MeV respectively, then the energy released in the reaction P+Q→R is

2MeV

12MeV

241MeV

22MeV