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Q. If binding energy of hypothetical nuclei $P,Q$ and $R$ are $112MeV,106MeV$ and $230MeV$ respectively, then the energy released in the reaction $P+Q \rightarrow R$ is

NTA AbhyasNTA Abhyas 2022

Solution:

From the given reaction,
$P+Q \rightarrow R$
The binding energy is the difference of energies between reactant and product,
$\Rightarrow 230-\left(\right.112+106\left.\right)=12MeV$