Q.
If ⎩⎨⎧⎣⎡571163425⎦⎤⎣⎡16−7624−743⎦⎤⎣⎡514762135⎦⎤⎭⎬⎫2020=⎣⎡a1b1c1a2b2c2a3b3c3⎦⎤ , then the value of 2∣a2−b1∣+3∣a3−c1∣+4∣b3−c2∣ is equal to
2275
208
NTA AbhyasNTA Abhyas 2020Matrices
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Solution:
Let, X=(ABAT)2020
( ∵B is symmetric) XT=((ABAT)2020)T=((ABAT)T)2020=(ABAT)2020 X=XT⇒X is a symmetric matrix ⇒a2=b1,a3=c1,b3=c2 ⇒ Required value =0