If B is a natural number and it can be expressed as the sum of the first A consecutive odd natural numbers, then the value of B-A2 is

Question

If B is a natural number and it can be expressed as the sum of the first A consecutive odd natural numbers, then the value of B-A2 is  (A) 1 (B) B (C) A (D) 0

Tardigrade Admin · Accepted Answer

Given B is a natural number. The sum of the first A consecutive odd numbers required to give the sum equal to B. ∴ A2=B (successive subtraction method) ∴ B-A2=0

Q. If $B$ is a natural number and it can be expressed as the sum of the first $A$ consecutive odd natural numbers, then the value of $B - A^{2}$ is __

1

$B$

$A$

0

Given $B$ is a natural number.
The sum of the first $A$ consecutive odd numbers required to give the sum equal to $B$ .
$∴ A^{2} = B$ (successive subtraction method)
$∴ B - A^{2} = 0$

Q. If B is a natural number and it can be expressed as the sum of the first A consecutive odd natural numbers, then the value of B−A2 is __

1

B

A

0

Given B is a natural number. The sum of the first A consecutive odd numbers required to give the sum equal to B. ∴A2=B (successive subtraction method) ∴B−A2=0

Q. If $B$ is a natural number and it can be expressed as the sum of the first $A$ consecutive odd natural numbers, then the value of $B - A^{2}$ is __

$B$

$A$

Given $B$ is a natural number.
The sum of the first $A$ consecutive odd numbers required to give the sum equal to $B$ .
$∴ A^{2} = B$ (successive subtraction method)
$∴ B - A^{2} = 0$