If b a, then the equation (x - a) (x - b) - 1 = 0 has

Question

If b > a, then the equation (x - a) (x - b) - 1 = 0 has (A) both roots in (a, b) (B) both roots in (- ∞, a) (C) both roots in (b, + ∞) (D) one root in (- ∞, a) and the other in (b, ∞)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/8dc972c908c02746971d42b73e86f9a8-.png" /> From graph, it is clear that one of the roots of (x-a)(x-b)-1=0 lies in (-∞, a) and other lies in (b, ∞)

Q. If $b > a,$ then the equation $(x - a) (x - b) - 1 = 0$ has

both roots in (a, b)

both roots in $(- \infty, a)$

both roots in $(b, + \infty)$

one root in $(- \infty, a)$ and the other in $(b, \infty)$

From graph, it is clear that one of the roots of $(x - a) (x - b) - 1 = 0$ lies in $(- \infty, a)$ and other lies in $(b, \infty)$

Q. If b>a, then the equation (x−a)(x−b)−1=0 has

both roots in (a, b)

both roots in (−∞,a)

both roots in (b,+∞)

one root in (−∞,a) and the other in (b,∞)

From graph, it is clear that one of the roots of (x−a)(x−b)−1=0 lies in (−∞,a) and other lies in (b,∞)

Q. If $b > a,$ then the equation $(x - a) (x - b) - 1 = 0$ has

both roots in $(- \infty, a)$

both roots in $(b, + \infty)$

one root in $(- \infty, a)$ and the other in $(b, \infty)$

From graph, it is clear that one of the roots of $(x - a) (x - b) - 1 = 0$ lies in $(- \infty, a)$ and other lies in $(b, \infty)$