If an electron of hydrogen atom moves from fourth excited state to ground state in Lymen series find the total number of spectral lines?

Question

If an electron of hydrogen atom moves from fourth excited state to ground state in Lymen series find the total number of spectral lines? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Total number of spectral lines =(n (n - 1)/2)=(5 (5 - 1)/2)=10

Q. If an electron of hydrogen atom moves from fourth excited state to ground state in Lymen series find the total number of spectral lines?

Total number of spectral lines $= \frac{n ( n - 1 )}{2} = \frac{5 ( 5 - 1 )}{2} = 10$

Q. If an electron of hydrogen atom moves from fourth excited state to ground state in Lymen series find the total number of spectral lines?

Total number of spectral lines =2n(n−1)​=25(5−1)​=10

Total number of spectral lines $= \frac{n ( n - 1 )}{2} = \frac{5 ( 5 - 1 )}{2} = 10$