If an electron has orbital angular momentum quantum number l=7 then it will have an orbital angular momentum equal to:

Question

If an electron has orbital angular momentum quantum number l=7 then it will have an orbital angular momentum equal to: (A) √56((h/2 π)) (B) 57((h/2 π)) (C)  42( (h/2π ) )  (D)  7( (h/2π ) )

Tardigrade Admin · Accepted Answer

L=√l(l+1) ⋅ (h/2 π) =√7 × 8 (h/2 π) =√56 (h/2 π)

Q. If an electron has orbital angular momentum quantum number $l = 7$ then it will have an orbital angular momentum equal to:

$56 (\frac{h}{2 π})$

$57 (\frac{h}{2 π})$

$42 (\frac{h}{2 π})$

$7 (\frac{h}{2 π})$

$L = l (l + 1) \cdot \frac{h}{2 π}$
$= 7 \times 8 \frac{h}{2 π}$
$= 56 \frac{h}{2 π}$

Q. If an electron has orbital angular momentum quantum number l=7 then it will have an orbital angular momentum equal to:

56​(2πh​)

57(2πh​)

42(2πh​)

7(2πh​)