Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If α, β, γ, δ are the roots of the equation x 4+ x 3+ x 2+ x +1=0, then α2021+β2021+γ2021+δ2021 is equal to .
Q. If
α
,
β
,
γ
,
δ
are the roots of the equation
x
4
+
x
3
+
x
2
+
x
+
1
=
0
, then
α
2021
+
β
2021
+
γ
2021
+
δ
2021
is equal to .
893
114
JEE Main
JEE Main 2022
Complex Numbers and Quadratic Equations
Report Error
A
−
4
B
−
1
C
1
D
4
Solution:
α
,
β
,
γ
,
δ
root of the equation
x
4
+
x
3
+
x
2
+
x
+
1
=
0
Which are
5
th
roots of unity except 1 . then
α
2021
+
β
2021
+
γ
2021
+
δ
2021
=
α
+
β
+
γ
+
δ
=
−
1