If α, β are the roots of x2-p(x+1)-c=0, c ≠ 1, then the value of (α+1)(β+1) is equal to:

Question

If α, β are the roots of x2-p(x+1)-c=0, c ≠ 1, then the value of (α+1)(β+1) is equal to: (A) 1- c (B) p+c (C) 1+ c (D) 1-2 p

Tardigrade Admin · Accepted Answer

The given equation may be written as x 2- px -( p + c )=0 ∴ α+β= p and α β=-( p + c ) Now, (α+1)(β+1)=α β+α+β+1 =- p - c + p +1=1- c

Q. If $α, β$ are the roots of $x^{2} - p (x + 1) - c = 0, c \neq = 1$ , then the value of $(α + 1) (β + 1)$ is equal to: