Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If α and β are roots of the equation x2 + x + 1 = 0 then α2 + β2 is
Q. If
α
and
β
are roots of the equation
x
2
+
x
+
1
=
0
then
α
2
+
β
2
is
1647
275
KCET
KCET 2019
Complex Numbers and Quadratic Equations
Report Error
A
2
−
1
−
i
3
13%
B
1
26%
C
-1
38%
D
2
−
1
+
i
3
22%
Solution:
x
2
+
x
+
1
=
0
⇒
x
=
α
,
β
=
α
2
w
h
ere
α
i
s
t
h
e
c
u
b
e
roo
t
o
f
u
ni
t
y
α
2
+
β
2
=
ω
2
+
ω
4
=
ω
2
+
ω
=
−
1