If all the six digit numbers x1 x2 x3 x4 x5 x6 with 0

Question

If all the six digit numbers x1 x2 x3 x4 x5 x6 with 0 < x1 < x2 < x3 < x4 < x5 < x6 are arranged in the increasing order, then the sum of the digits in the 72 text th number is  (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/88c92a1f8bf8392a8f85b261bc9b8602-.png" /> 245678 arrow 72 text th text word 2+4+5+6+7+8=32

Q. If all the six digit numbers $x_{1} x_{2} x_{3} x_{4} x_{5} x_{6}$ with $0 < x_{1} < x_{2} < x_{3} < x_{4} < x_{5} < x_{6}$ are arranged in the increasing order, then the sum of the digits in the $7 2^{th}$ number is _____

$245678 \to 7 2^{th} word$
$2 + 4 + 5 + 6 + 7 + 8 = 32$

Q. If all the six digit numbers x1​x2​x3​x4​x5​x6​ with 0<x1​<x2​<x3​<x4​<x5​<x6​ are arranged in the increasing order, then the sum of the digits in the 72th number is _____

245678→72th word 2+4+5+6+7+8=32

Q. If all the six digit numbers $x_{1} x_{2} x_{3} x_{4} x_{5} x_{6}$ with $0 < x_{1} < x_{2} < x_{3} < x_{4} < x_{5} < x_{6}$ are arranged in the increasing order, then the sum of the digits in the $7 2^{th}$ number is _____

$245678 \to 7 2^{th} word$
$2 + 4 + 5 + 6 + 7 + 8 = 32$