If ABCDEF is a regular hexagon and AB + AC + AD + AE + AF = n AD . Then n is

Question

If ABCDEF is a regular hexagon and AB + AC + AD + AE + AF = n AD . Then n is (A) 1 (B) 2 (C) 3 (D) (5/2)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/mathematics/3583179fc9c0d00fdd7032b6f6d8fe10-.png" /> AB + AC + AD + AE + AF = ED + AC + AD + AE + CD =( AC + CD )+ AD + AE + ED ) = AD + AD + AD =3 AD ∴ n =3

Q. If $A BC D EF$ is a regular hexagon and $A B + A C + A D + A E + A F = n A D$ . Then $n$ is

1

2

3

$\frac{5}{2}$

$A B + A C + A D + A E + A F$
$= E D + A C + A D + A E + C D$
$= (A C + C D) + A D + A E + E D)$
$= A D + A D + A D = 3 A D$
$∴ n = 3$

Q. If ABCDEF is a regular hexagon and AB+AC+AD+AE+AF=nAD. Then n is

1

2

3

25​

AB+AC+AD+AE+AF =ED+AC+AD+AE+CD =(AC+CD)+AD+AE+ED) =AD+AD+AD=3AD ∴n=3

Q. If $A BC D EF$ is a regular hexagon and $A B + A C + A D + A E + A F = n A D$ . Then $n$ is

$\frac{5}{2}$

$A B + A C + A D + A E + A F$
$= E D + A C + A D + A E + C D$
$= (A C + C D) + A D + A E + E D)$
$= A D + A D + A D = 3 A D$
$∴ n = 3$