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Question
Mathematics
If ax = by = cz and a, b, c are in G.P. then x, y, z are in
Q. If
a
x
=
b
y
=
c
z
and
a
,
b
,
c
are in G.P. then
x
,
y
,
z
are in
2316
212
Sequences and Series
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A
A.P
20%
B
G.P
23%
C
H.P
54%
D
none of these.
3%
Solution:
a
x
=
b
y
=
c
z
=
K
(say)
⇒
a
=
K
x
1
,
b
=
K
y
1
,
c
=
K
z
1
.
⇒
Since
a
,
b
,
c
are in
G
.
P
.
⇒
b
2
=
a
c
⇒
K
y
2
=
K
x
1
⋅
K
z
1
=
K
x
1
+
z
1
⇒
y
2
=
x
1
+
z
1
⇒
x
1
,
y
1
,
z
1
are in
A
.
P
.
⇒
x
,
y
,
z
are in
H
.
P
.