If a vertex of a triangle is (1, 1) and the mid points of two sides through this vertex ate (-1, 2) and (3, 2), then the centroid of die triangle is:

Question

If a vertex of a triangle is (1, 1) and the mid points of two sides through this vertex ate (-1, 2) and (3, 2), then the centroid of die triangle is: (A) ((1/3), (7/3)) (B) (1, (7/3)) (C) (-(1/3), (7/3)) (D) (-1, (7/3))

Tardigrade Admin · Accepted Answer

If A(x1, y1), B(x2, y2) and C(x3, y3) are the vertices of a triangle, then the co-ordinates of the centroid will be ((x1+x2+x3/3), (y1+y2+y3/3)). Let D and E are mid points of AB and AC. So co-ordinates of B and C are (- 3, 3) and (5, 3) respectively. Centroid of triangle = ((x1+x2+x3/3), (y1+y2+y3/3)) = ((1-3+5/3), (1+3+3/3)) = (1, (7/3))

Q. If a vertex of a triangle is (1, 1) and the mid points of two sides through this vertex ate (-1, 2) and (3, 2), then the centroid of die triangle is:

$(\frac{1}{3}, \frac{7}{3})$

$(1, \frac{7}{3})$

$(- \frac{1}{3}, \frac{7}{3})$

$(- 1, \frac{7}{3})$

Q. If a vertex of a triangle is (1, 1) and the mid points of two sides through this vertex ate (-1, 2) and (3, 2), then the centroid of die triangle is:

(31​,37​)

(1,37​)

(−31​,37​)

(−1,37​)

$(\frac{1}{3}, \frac{7}{3})$

$(1, \frac{7}{3})$

$(- \frac{1}{3}, \frac{7}{3})$

$(- 1, \frac{7}{3})$