Q.
If a velocity has both perpendicular and parallel components while moving through a magnetic field, what is the path followed by a charged particle ?
Suppose, the velocity v of the particle entering the field B, instead of being perpendicular to B, makes an angle θ with it.
Then v may be resolved into two components, V∣∣=vcosθ parallel to B and v⊥=vsinθ
perpendicular to B. The component V∥ gives a linear path and the component V⊥ gives a circular path to the particle. The resultant of these two is a helical path whose axis is parallel to the magnetic field.