If a stretched wire is vibrating in the second overtone, then the number of nodes and antinodes between the ends of the string are respectively

Question

If a stretched wire is vibrating in the second overtone, then the number of nodes and antinodes between the ends of the string are respectively (A) 2 and 2 (B) 1 and 2 (C) 4 and 3 (D) 2 and 3

Tardigrade Admin · Accepted Answer

For third harmonic second overtone <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/6d29d27b46f40b9ca06b55d5bd217d42-.png" /> So, the number of nodes =4 N and the number of antinodes =3 A NOTE Ambiguous statement in question. Our solution considers the end nodes also.

Q. If a stretched wire is vibrating in the second overtone, then the number of nodes and antinodes between the ends of the string are respectively

2 and 2

1 and 2

4 and 3

2 and 3

3 and 4

For third harmonic second overtone

So, the number of nodes $= 4 N$
and the number of antinodes $= 3 A$
NOTE Ambiguous statement in question. Our solution considers the end nodes also.