If a straight line passing through the point P(-3, 4) is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is :

Question

If a straight line passing through the point P(-3, 4) is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is : (A) x - y + 7 = 0 (B) 3x - 4y + 25 = 0 (C) 4x + 3y = 0 (D) 4x - 3y + 24 = 0

Tardigrade Admin · Accepted Answer

Let the line be (x/a) + (y/b) = 1 (-3, 4) = ((a/2), (b/2)) a = -6, b = 8 equation of line is 4x - 3y + 24 = 0

Q. If a straight line passing through the point $P (- 3, 4)$ is such that its intercepted portion between the coordinate axes is bisected at $P$ , then its equation is :

x - y + 7 = 0

3x - 4y + 25 = 0

4x + 3y = 0

4x - 3y + 24 = 0

Let the line be $\frac{x}{a} + \frac{y}{b} = 1$
$(- 3, 4) = (\frac{a}{2}, \frac{b}{2})$
a = -6, b = 8
equation of line is 4x - 3y + 24 = 0

Q. If a straight line passing through the point P(−3,4) is such that its intercepted portion between the coordinate axes is bisected at P, then its equation is :