Question

If a spring extends by x on loading, then energy stored by the spring is (if $T$ is the tension in the spring and $k$ is the spring constant)

• A. $\frac{T^2}{2x}$
• B. $\frac{T^2}{2k}$
• C. $\frac{2k}{T^2}$
• D. $\frac{2T^2}{k}$

Answer 1

Answer: (B)

Extension of spring $=x$, fension on spring $=T$ and spring constant $=k.$ Now extension of spring $x=\frac{T}{k}$ and energy stored by the spring
$E=\frac{1}{2}\times k{x}^2=\frac{1}{2}\times k\times {\left(\frac{T}{k}\right)}^2=\frac{1}{2}\times k\times \frac{T^2}{k^2}=\frac{T^2}{2k}$.