If a source of power 4 kW produces 1020 photons/second, the radiation belong to a part of the spectrum called

Question

If a source of power 4 kW produces 1020 photons/second, the radiation belong to a part of the spectrum called (A) X-rays (B) ultraviolet rays (C) microwaves (D) &gamma;-rays

Tardigrade Admin · Accepted Answer

4 × 103 = 1020 × hf f = (4 × 103 /1020× 6.023× 10-34) f = 6.03 × 1016 Hz The obtained frequency lies in the band of X-rays.

Q. If a source of power $4 kW$ produces $1 0^{20}$ photons/second, the radiation belong to a part of the spectrum called

X-rays

ultraviolet rays

microwaves

$γ$ -rays

$4 \times 1 0^{3} = 1 0^{20} \times h f$
$f = \frac{4 \times 1 0 ^{3}}{1 0 ^{20} \times 6.023 \times 1 0 ^{- 34}}$
$f = 6.03 \times 1 0^{16} Hz$
The obtained frequency lies in the band of X-rays.

Q. If a source of power 4kW produces 1020 photons/second, the radiation belong to a part of the spectrum called