If a source of electromagnetic radiation having power 15 kW produces 1016 photons per second, the radiation belongs to a part of spectrum is. (Take Planck constant h =6 × 10-34 Js )

Question

If a source of electromagnetic radiation having power 15 kW produces 1016 photons per second, the radiation belongs to a part of spectrum is. (Take Planck constant h =6 × 10-34 Js ) (A) Micro waves (B) Gamma rays (C) Radio waves (D) Ultraviolet rays

Tardigrade Admin · Accepted Answer

text Energy of one photon =( text Power / text Photon frequency ) E=h v=(15 × 103/1016) v=(15 × 10-13/6 × 10-34)=2.5 × 1021 So gamma Rays. Option 3

Q. If a source of electromagnetic radiation having power $15 kW$ produces $1 0^{16}$ photons per second, the radiation belongs to a part of spectrum is. (Take Planck constant $h = 6 \times 1 0^{- 34} J s$ )

Micro waves

Gamma rays

Radio waves

Ultraviolet rays

$Energy of one photon = \frac{Power}{Photon frequency}$
$E = h v = \frac{15 \times 1 0 ^{3}}{1 0 ^{16}}$
$v = \frac{15 \times 1 0 ^{- 13}}{6 \times 1 0 ^{- 34}} = 2.5 \times 1 0^{21}$
So gamma Rays. Option 3

Q. If a source of electromagnetic radiation having power 15kW produces 1016 photons per second, the radiation belongs to a part of spectrum is. (Take Planck constant h=6×10−34Js )