Let mass of solution =100g, ∴ Mass of glucose =10g,
Mass of water =90g
No. of moles of 10g glucose=10810=0.0555 mol,
No. of moles of H2O=1890=5 mol
Volume of solution =1.2mL100=83.33mL=0.0833L
Molality =Mass of solvent in kgnumber of moles of solute =0.090kg0.0555mol