If a rubber ball is taken at the depth of 200m in a pool, its volume decreases by 0.1%. If the density of water is text1 ! !× ! ! text 1 text0 text3 textkg/ textm text3 and g=10 m/s2, then the volume of elasticity in textN/ textm text2 will be

Question

If a rubber ball is taken at the depth of 200m in a pool, its volume decreases by 0.1%. If the density of water is text1 ! !× ! ! text 1 text0 text3 textkg/ textm text3 and g=10 m/s2, then the volume of elasticity in textN/ textm text2 will be (A)  text1 text08  (B)  text2× text1 text08  (C)  text1 text09  (D)  text2× text1 text09

Tardigrade Admin · Accepted Answer

K=(Δ p/Δ V/V)=(ρ hg/Δ V/V) =(200× 103× 10/0.1/100) =2× 109

Q. If a rubber ball is taken at the depth of 200m in a pool, its volume decreases by 0.1%. If the density of water is $1 \times 1 0^{3} kg/ m^{3}$ and $g = 10 m / s^{2},$ then the volume of elasticity in $N/ m^{2}$ will be

$1 0^{8}$

$2 \times 1 0^{8}$

$1 0^{9}$

$2 \times 1 0^{9}$

$K = \frac{Δ p}{Δ V / V} = \frac{ρ h g}{Δ V / V}$
$= \frac{200 \times 10 ^{3} \times 10}{0.1/100}$
$= 2 \times 10^{9}$

Q. If a rubber ball is taken at the depth of 200m in a pool, its volume decreases by 0.1%. If the density of water is 1 × 103kg/m3 and g=10m/s2, then the volume of elasticity in N/m2 will be

108

2×108

109

2×109