If a relation R is defined from a set A = 2,3,4,5 to a set B = 3,6,7,10 as follows (x,y) ∈ R Leftrightarrow x divides y. Expression of R-1 is represented by

Question

If a relation R is defined from a set A = 2,3,4,5 to a set B = 3,6,7,10 as follows (x,y) ∈ R Leftrightarrow x divides y. Expression of R-1 is represented by (A)  (6,2), (10,2), (3,3), (6,3)  (B)  (6,2), (3, 3), (10, 5), (10, 2)  (C)  (6,2), (10,2), (3,3), (6,3), (10,5)  (D) None of these

Tardigrade Admin · Accepted Answer

Recall that a/b stands for a divides b. For the elements of the given sets A and B, we find 2/6, 2/10, 3/3, 3/6, 5/10 ⇒ R = (2,6), (2,10), (3, 3), (3,6), (5,10) ∴ R-1= (6, 2), (10,2), (3, 3), (6, 3), (10,5)

Q. If a relation $R$ is defined from a set $A = {2, 3, 4, 5}$ to a set $B = {3, 6, 7, 10}$ as follows $(x, y) \in R \Leftrightarrow x$ divides $y$ . Expression of $R^{- 1}$ is represented by

${(6, 2), (10, 2), (3, 3), (6, 3)}$

${(6, 2), (3, 3), (10, 5), (10, 2)}$

${(6, 2), (10, 2), (3, 3), (6, 3), (10, 5)}$

None of these

Recall that $a / b$ stands for $a$ divides $b$ . For the elements of the given sets $A$ and $B$ , we find $2/6$ , $2/10$ , $3/3$ , $3/6$ , $5/10$
$\Rightarrow R = {(2, 6), (2, 10), (3, 3), (3, 6), (5, 10)}$
$∴ R^{- 1} = {(6, 2), (10, 2), (3, 3), (6, 3), (10, 5)}$

Q. If a relation R is defined from a set A={2,3,4,5} to a set B={3,6,7,10} as follows (x,y)∈R⇔x divides y. Expression of R−1 is represented by

{(6,2),(10,2),(3,3),(6,3)}

{(6,2),(3,3),(10,5),(10,2)}

{(6,2),(10,2),(3,3),(6,3),(10,5)}