If a pure compound is composed of X2Y3 molecules and consists of 60 % X by weight what is the atomic weight of Y is term of atomic weight of X (molecular mass of X=Mx )?

Question

If a pure compound is composed of X2Y3 molecules and consists of 60 % X by weight what is the atomic weight of Y is term of atomic weight of X (molecular mass of X=Mx )? (A) (9/4)Mx (B) (4/9)Mx (C) (2/3)Mx (D) (3/2)Mx

Tardigrade Admin · Accepted Answer

Element % weight % mole X 60 60/Mx Y 40 40/My given (60/Mx/40/My)=(2/3)⇒ (My/Mx)=(4/9) My=(4/9)Mx

Element	$%$ weight	$%$ mole
$X$	$60$	$60/ M_{x}$
$Y$	$40$	$40/ M_{y}$

Q. If a pure compound is composed of $X_{2} Y_{3}$ molecules and consists of $60%$ X by weight what is the atomic weight of $Y$ is term of atomic weight of $X$ (molecular mass of $X = M_{x}$ )?

$\frac{9}{4} M_{x}$

$\frac{4}{9} M_{x}$

$\frac{2}{3} M_{x}$

$\frac{3}{2} M_{x}$

Element $%$ weight $%$ mole

$X$ $60$ $60/ M_{x}$

$Y$ $40$ $40/ M_{y}$

given $\frac{60/ M _{x}}{40/ M _{y}} = \frac{2}{3} \Rightarrow \frac{M _{y}}{M _{x}} = \frac{4}{9}$
$M_{y} = \frac{4}{9} M_{x}$

Q. If a pure compound is composed of X2​Y3​ molecules and consists of 60% X by weight what is the atomic weight of Y is term of atomic weight of X (molecular mass of X=Mx​ )?

49​Mx​

94​Mx​

32​Mx​

23​Mx​