If a positively charged pendulum is oscillating in a uniform electric field as shown in diagram. Its frequency compared to that when it was uncharged-

Question

If a positively charged pendulum is oscillating in a uniform electric field as shown in diagram. Its frequency compared to that when it was uncharged- <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/9fd65c1e2199a12455d840748cb9b92e-.png" /> (A) Will increase (B) Will decrease (C) Will not change (D) Will first increase and then decrease

Tardigrade Admin · Accepted Answer

T =2 π √(ℓ/ g eff ) =2 π √(ℓ/ q +( qE ) m ) Hence time period decreases and frequency increases.

Q. If a positively charged pendulum is oscillating in a uniform electric field as shown in diagram. Its frequency compared to that when it was uncharged-

Will increase

Will decrease

Will not change

Will first increase and then decrease

$T = 2 π \frac{ℓ}{g _{e ff}}$
$= 2 π \frac{ℓ}{q + \frac{qE}{m}}$
Hence time period decreases and frequency increases.

Q. If a positively charged pendulum is oscillating in a uniform electric field as shown in diagram. Its frequency compared to that when it was uncharged-

Will increase

Will decrease

Will not change

Will first increase and then decrease

T=2πgeff​ℓ​​ =2πq+mqE​ℓ​​ Hence time period decreases and frequency increases.

$T = 2 π \frac{ℓ}{g _{e ff}}$
$= 2 π \frac{ℓ}{q + \frac{qE}{m}}$
Hence time period decreases and frequency increases.