Question

If a polygon have number of sides 6, how many diagonals will this polygon have?

• A. 8
• B. 5
• C. 9
• D. None of these

Answer 1

Answer: (C)

$\text{ Number of diagonal }=\frac{n(n-3)}{2}=\frac{6(6-3)}{2}$
$=3\times 3=9$