If a person is pushing a box inside a moving train, the work done in the frame of earth will be vecs0=displacement of the train relative to ground. vecs=displacement of the box w.r.t. train

Question

If a person is pushing a box inside a moving train, the work done in the frame of earth will be vecs0=displacement of the train relative to ground. vecs=displacement of the box w.r.t. train (A) Zero (B)  vecF.( vecs+ vecs0) (C)  vecF. vecs (D)  vecF. vecs0

Tardigrade Admin · Accepted Answer

Displacement w.r.t. ground = vecs+ vecs0 Since train is moving with constant velocity net force acting on block is = vecF Therefore work done = vecF.( vecs+ vecs0)

Q. If a person is pushing a box inside a moving train, the work done in the frame of earth will be
$s_{0} =$ displacement of the train relative to ground.
$s =$ displacement of the box w.r.t. train

Zero

$F . (s + s_{0})$

$F . s$

$F . s_{0}$

Displacement w.r.t. ground $= s + s_{0}$

Since train is moving with constant velocity net force acting on block is $= F$

Therefore work done $= F . (s + s_{0})$

Q. If a person is pushing a box inside a moving train, the work done in the frame of earth will be s0​​=displacement of the train relative to ground. s=displacement of the box w.r.t. train

Zero

F.(s+s0​​)

F.s

F.s0​​

Displacement w.r.t. ground =s+s0​​ Since train is moving with constant velocity net force acting on block is =F Therefore work done =F.(s+s0​​)

Q. If a person is pushing a box inside a moving train, the work done in the frame of earth will be
$s_{0} =$ displacement of the train relative to ground.
$s =$ displacement of the box w.r.t. train

$F . (s + s_{0})$

$F . s$

$F . s_{0}$

Displacement w.r.t. ground $= s + s_{0}$

Since train is moving with constant velocity net force acting on block is $= F$

Therefore work done $= F . (s + s_{0})$