If a particle takes 0.5 sec to reach position of minimum velocity from previous such position, then

Question

If a particle takes 0.5 sec to reach position of minimum velocity from previous such position, then (A) T=6 sec , v=1 / 6 Hz (B) T =2 sec , v=1 Hz (C) T =3 sec , v =3 Hz (D) T=1 sec , v =1 Hz

Tardigrade Admin · Accepted Answer

(T/2)=0.5 sec ⇒ T =1 sec v=(1/T)=1 Hz

Q. If a particle takes $0.5 sec$ to reach position of minimum velocity from previous such position, then

$T = 6 sec, v = 1/6 Hz$

$T = 2 sec, v = 1 Hz$

$T = 3 sec, v = 3 Hz$

$T = 1 sec, v = 1 Hz$

$\frac{T}{2} = 0.5 sec \Rightarrow T = 1 sec$
$v = \frac{1}{T} = 1 Hz$

Q. If a particle takes 0.5sec to reach position of minimum velocity from previous such position, then

T=6sec,v=1/6Hz

T=2sec,v=1Hz

T=3sec,v=3Hz

T=1sec,v=1Hz