If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be

Question

If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be (A) 2: 1 (B) 1: 2 (C) 1: 3 (D) 3: 1

Tardigrade Admin · Accepted Answer

N 2( g )+3 H 2( g ) leftharpoons 2 NH 3( g ) As 4 moles of reactants form of 2 moles of product, so ratio of volumes of reactants and products at the same temperature and pressure would be 2: 1 or 4: 2.

Q. If a mixture containing $3$ moles of hydrogen and $1$ mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be

$2 : 1$

$1 : 2$

$1 : 3$

$3 : 1$

$N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)$
As $4$ moles of reactants form of $2$ moles of product, so ratio of volumes of reactants and products at the same temperature and pressure would be $2 : 1$ or $4 : 2$ .

Q. If a mixture containing 3 moles of hydrogen and 1 mole of nitrogen is converted completely into ammonia, the ratio of volumes of reactants and products at the same temperature and pressure would be

2:1

1:2

1:3

3:1