Q. If a machine gun fires $n$ bullets per second each with kinetic energy K, then the power of the machine gun is

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A

$n K^{2}$

0%

B

$\frac{K}{n}$

0%

C

$n^{2} K$

50%

D

$n K$

50%

E

$\frac{n}{K}$

50%

Solution:

Correct answer is (d) $n K$