If a =( log 81 16/ log 3 2), b =((1/3 log 3 2))((1/7 log 7 0.1)) and c =( log 8 125/ log 8 5) then the value of a + b ÷ c is equal to

Question

If a =( log 81 16/ log 3 2), b =((1/3 log 3 2))((1/7 log 7 0.1)) and c =( log 8 125/ log 8 5) then the value of a + b ÷ c is equal to (A) 1 (B) 2 (C) (7/3) (D) (8/3)

Tardigrade Admin · Accepted Answer

a =1, b =(1/2) × (1/0.1)=5 and c =3 ∴ a + b ÷ c =1+(5/3)=(8/3)

Q. If $a = \frac{l o g _{81} 16}{l o g _{3} 2}, b = (\frac{1}{3 ^{l o g_{3} 2}}) (\frac{1}{7 ^{l o g_{7} 0.1}})$ and $c = \frac{l o g _{8} 125}{l o g _{8} 5}$ then the value of $a + b \div c$ is equal to

1

2

$\frac{7}{3}$

$\frac{8}{3}$

$a = 1, b = \frac{1}{2} \times \frac{1}{0.1} = 5$ and $c = 3$
$∴ a + b \div c = 1 + \frac{5}{3} = \frac{8}{3}$

Q. If a=log3​2log81​16​,b=(3log3​21​)(7log7​0.11​) and c=log8​5log8​125​ then the value of a+b÷c is equal to

1

2

37​

38​

a=1,b=21​×0.11​=5 and c=3 ∴a+b÷c=1+35​=38​

Q. If $a = \frac{l o g _{81} 16}{l o g _{3} 2}, b = (\frac{1}{3 ^{l o g_{3} 2}}) (\frac{1}{7 ^{l o g_{7} 0.1}})$ and $c = \frac{l o g _{8} 125}{l o g _{8} 5}$ then the value of $a + b \div c$ is equal to

$\frac{7}{3}$

$\frac{8}{3}$

$a = 1, b = \frac{1}{2} \times \frac{1}{0.1} = 5$ and $c = 3$
$∴ a + b \div c = 1 + \frac{5}{3} = \frac{8}{3}$