Question

If $a=\frac{{\log }_{81}16}{{\log }_{3}2},b=\left(\frac{1}{3^{{\log }_{3}2}}\right)\left(\frac{1}{7^{{\log }_{7}0.1}}\right)$ and $c=\frac{{\log }_{8}125}{{\log }_{8}5}$ then the value of $a+b÷c$ is equal to

• A. 1
• B. 2
• C. $\frac{7}{3}$
• D. $\frac{8}{3}$

Answer 1

Answer: (D)

$a=1,b=\frac{1}{2}\times \frac{1}{0.1}=5$ and $c=3$
$\therefore a+b÷c=1+\frac{5}{3}=\frac{8}{3}$