Question

If $a =\frac{\log _{81} 16}{\log _3 2}, b =\left(\frac{1}{3^{\log _3 2}}\right)\left(\frac{1}{7^{\log _7 0.1}}\right)$ and $c =\frac{\log _8 125}{\log _8 5}$ then the value of $a + b \div c$ is equal to

• A. 1
• B. 2
• C. $\frac{7}{3}$
• D. $\frac{8}{3}$

Answer 1

Answer: (D)

$a =1, b =\frac{1}{2} \times \frac{1}{0.1}=5$ and $c =3$
$\therefore a + b \div c =1+\frac{5}{3}=\frac{8}{3}$