If a line with y-intercept 2, is perpendicular to the line 3x-2y=6, then its x- intercept is

Question

If a line with y-intercept 2, is perpendicular to the line 3x-2y=6, then its x- intercept is (A) 1 (B) 2 (C)  -4  (D) 4

Tardigrade Admin · Accepted Answer

Let the equation of perpendicular line to the line 3x-2y=6 is 3y+2x=c Since, it passes through (0, 2) ∴ 6=c ∴ 3y+2x=6 ⇒ (x/3)+(y/2)=1 Hence, x- intercept is 3.

Q. If a line with $y$ -intercept $2$ , is perpendicular to the line $3 x - 2 y = 6,$ then its $x -$ intercept is

1

2

$- 4$

4

3

Let the equation of perpendicular line to the line
$3 x - 2 y = 6$ is $3 y + 2 x = c$
Since, it passes through (0, 2)
$∴$ $6 = c$
$∴$ $3 y + 2 x = 6$
$\Rightarrow$ $\frac{x}{3} + \frac{y}{2} = 1$
Hence, $x -$ intercept is 3.

Q. If a line with y-intercept 2, is perpendicular to the line 3x−2y=6, then its x− intercept is

1

2

−4

4

3

Let the equation of perpendicular line to the line 3x−2y=6 is 3y+2x=c Since, it passes through (0, 2) ∴ 6=c ∴ 3y+2x=6 ⇒ 3x​+2y​=1 Hence, x− intercept is 3.

Q. If a line with $y$ -intercept $2$ , is perpendicular to the line $3 x - 2 y = 6,$ then its $x -$ intercept is

$- 4$

Let the equation of perpendicular line to the line
$3 x - 2 y = 6$ is $3 y + 2 x = c$
Since, it passes through (0, 2)
$∴$ $6 = c$
$∴$ $3 y + 2 x = 6$
$\Rightarrow$ $\frac{x}{3} + \frac{y}{2} = 1$
Hence, $x -$ intercept is 3.