If a light ray incidents normally on one of the faces of the prism of refractive index 2 and the emergent ray just grazes the second face of the prism, then the angle of deviation is

Question

If a light ray incidents normally on one of the faces of the prism of refractive index 2 and the emergent ray just grazes the second face of the prism, then the angle of deviation is (A) 0° (B) 300 (C) 45° (D) 600

Tardigrade Admin · Accepted Answer

sin c=(1/μ)=(1/2) ⇒ C=30° r1+r2=A 0+c=A ⇒ A=30° i1+i2=A+d 0+90=30+d ⇒ d=60°

Q. If a light ray incidents normally on one of the faces of the prism of refractive index $2$ and the emergent ray just grazes the second face of the prism, then the angle of deviation is

$0^{\circ}$

$3 0^{0}$

$4 5^{\circ}$

$6 0^{0}$

$sin c = \frac{1}{μ} = \frac{1}{2}$
$\Rightarrow C = 3 0^{\circ}$
$r_{1} + r_{2} = A$
$0 + c = A$
$\Rightarrow A = 3 0^{\circ}$
$i_{1} + i_{2} = A + d$
$0 + 90 = 30 + d$
$\Rightarrow d = 6 0^{\circ}$

Q. If a light ray incidents normally on one of the faces of the prism of refractive index 2 and the emergent ray just grazes the second face of the prism, then the angle of deviation is

0∘

300

45∘

600