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Tardigrade
Question
Mathematics
If A is a 3 × 3 non-singular matrix, then mid A-1 adj A mid is
Q. If
A
is a
3
×
3
non-singular matrix, then
∣
A
−
1
adj
A
∣
is
226
157
Determinants
Report Error
A
∣
A
∣
34%
B
1
10%
C
∣
A
∣
2
37%
D
∣
A
∣
−
1
20%
Solution:
∣
A
−
1
adj
A
∣=
∣
∣
A
−
1
∣
∣
⋅
adj
A
∣
(
∵
∣
A
B
∣
=
∣
A
∣
⋅
∣
B
∣
)
=
∣
A
∣
−
1
∣
adj
A
∣
(
∵
∣
∣
A
−
1
∣
∣
=
∣
A
∣
−
1
)
=
∣
A
∣
−
1
⋅
∣
A
∣
2
(
∵
A
is a
3
×
3
non-singular matrix, so
∣
adj
A
∣
=
∣
A
∣
2
)
=
∣
A
∣