Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If (a+i b)5=α+i β then (b+i a)5 is equal to
Q. If
(
a
+
ib
)
5
=
α
+
i
β
then
(
b
+
ia
)
5
is equal to
1924
166
Complex Numbers and Quadratic Equations
Report Error
A
β
+
i
α
37%
B
α
−
i
β
32%
C
β
−
i
α
25%
D
−
α
−
i
β
7%
Solution:
(
a
+
ib
)
5
=
α
+
i
β
i
5
(
b
−
ia
)
5
=
α
+
i
β
(
b
−
ia
)
5
=
−
i
α
+
β
(
b
+
ia
)
5
=
β
+
i
α