Question

If $a=\underset{x\to \pi /2}{\lim }\sqrt{\frac{\tan x-\sin \left({\tan }^{-1}(\tan x)\right)}{\tan x+{\cos }^2(\tan x)}}$ and $r=\frac{1}{{\lambda }^{\prime }}$ where $\lambda$ is the least integral value for which three real normal can be drawn to the parabola $y^2=8x$ from $(\lambda ,0)$, then.
Radius of the circle whose centre is $(a,\lambda )$ which touches the line $3x+4y=4$, is -

• A. 5
• B. 3
• C. 4
• D. 2

Answer 1

Answer: (B)

Correct answer is (b) 3