Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Mathematics
If A=[ cosθ sinθ -sinθ cosθ ] and A⋅ adj(A)=k[ 1 0 0 1 ] then k is
Q. If
A
=
[
cos
θ
−
s
in
θ
s
in
θ
cos
θ
]
and
A
⋅
a
d
j
(
A
)
=
k
[
1
0
0
1
]
then
k
is
48
151
NTA Abhyas
NTA Abhyas 2022
Report Error
A
1
B
3
C
2
D
4
Solution:
[
cos
θ
−
s
in
θ
s
in
θ
cos
θ
]
[
cos
θ
s
in
θ
−
s
in
θ
cos
θ
]
=
∣
A
∣
I
A
(
a
d
j
A
)
=
∣
A
∣
I
h
ere
∣
A
∣
=
1
⇒
K
=
1