If a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then average speed is

Question

If a car covers 2/5th of the total distance with v1 speed and 3/5th distance with v2 then average speed is (A) (1/2)√ν1 ν2 (B) (ν1+ν2/2) (C) (2ν1 ν2/ν1+ν2) (D) (5ν1 ν2/3ν1+2ν2)

Tardigrade Admin · Accepted Answer

Avg speed = (total distance/total times)

Q. If a car covers $2/ 5^{t h}$ of the total distance with $v_{1}$ speed and $3/ 5^{t h}$ distance with $v_{2}$ then average speed is

$\frac{1}{2} ν_{1} ν_{2}$

$\frac{ν _{1} + ν _{2}}{2}$

$\frac{2 ν _{1} ν _{2}}{ν _{1} + ν _{2}}$

$\frac{5 ν _{1} ν _{2}}{3 ν _{1} + 2 ν _{2}}$

$A vg$ speed = $\frac{t o t a l d i s t an ce}{t o t a l t im es}$

Q. If a car covers 2/5th of the total distance with v1​ speed and 3/5th distance with v2​ then average speed is

21​ν1​ν2​​

2ν1​+ν2​​

ν1​+ν2​2ν1​ν2​​

3ν1​+2ν2​5ν1​ν2​​