If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is:

Question

If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is: (A) inversely proportional to the square root of the displacement (B) inversely proportional to the displacement (C) directly proportional to the displacement (D) directly proportional to the square root of the displacement

Tardigrade Admin · Accepted Answer

Using s = ut + (1/2)at2 as initial velocity is zero hence. s = (1/2) at2 ⇒ t propto √s

Q. If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is:

inversely proportional to the square root of the displacement

inversely proportional to the displacement

directly proportional to the displacement

directly proportional to the square root of the displacement

Using $s = u t + \frac{1}{2} a t^{2}$ as initial velocity is zero hence.

$s = \frac{1}{2} a t^{2}$

$\Rightarrow t \propto s$

Q. If a body starts from rest, the time in which it covers a particular displacement with uniform acceleration is:

inversely proportional to the square root of the displacement

inversely proportional to the displacement

directly proportional to the displacement

directly proportional to the square root of the displacement

Using s=ut+21​at2 as initial velocity is zero hence. s=21​at2 ⇒t∝s​

Using $s = u t + \frac{1}{2} a t^{2}$ as initial velocity is zero hence.

$s = \frac{1}{2} a t^{2}$

$\Rightarrow t \propto s$