If a body of moment of inertia 2 kg m2 revolves about its own axis making 2 rotations per second, then its angular momentum (in Js) is

Question

If a body of moment of inertia 2 kg m2 revolves about its own axis making 2 rotations per second, then its angular momentum (in Js) is (A) 2 π (B) 4 π (C) 6 π (D) 8 π

Tardigrade Admin · Accepted Answer

Given, Moment of inertia of body (I)=2 kg m 2 Rotation of body in one second (f)=2 We know that, Angular momentum (L)=I ω L=2 × 2 π f L=2 × 2 π(2) L=8 π J / s

Q. If a body of moment of inertia $2 k g m^{2}$ revolves about its own axis making 2 rotations per second, then its angular momentum (in Js) is

$2 π$

$4 π$

$6 π$

$8 π$

$10 π$

Given,
Moment of inertia of body $(I) = 2 k g m^{2}$
Rotation of body in one second $(f) = 2$
We know that,
Angular momentum $(L) = I ω$
$L = 2 \times 2 π f$
$L = 2 \times 2 π (2)$
$L = 8 π J / s$

Q. If a body of moment of inertia 2kgm2 revolves about its own axis making 2 rotations per second, then its angular momentum (in Js) is

2π

4π

6π

8π

10π

Given, Moment of inertia of body (I)=2kgm2 Rotation of body in one second (f)=2 We know that, Angular momentum (L)=Iω L=2×2πf L=2×2π(2) L=8πJ/s