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Q. If a body of moment of inertia $2\, kg\, m^2$ revolves about its own axis making 2 rotations per second, then its angular momentum (in Js) is

KEAMKEAM 2016

Solution:

Given,
Moment of inertia of body $(I)=2\,kg \,m ^{2}$
Rotation of body in one second $(f)=2$
We know that,
Angular momentum $(L)=I \omega$
$L=2 \times 2 \pi f $
$L=2 \times 2 \pi(2)$
$L=8 \pi J / s$