Q.
If a be a repeated root of the quadratic equation f(x) = 0 and A(x), B(x), C(x) be polynomials of degrees 3, 4 and 5 respectively, then ∣∣A(x)A(a)A′(a)B(x)B(a)B′(a)C(x)C(a)C′(a)∣∣
We must have f(x)=k(x−a)2 where k is a constant. Now in order that the given determinant [Say, D(x)] be divisible by f(x) we must show that both D(x) and D'(x) vanish at x = a. Now D(a)=∣∣A(a)A(a)A′(a)B(a)B(a)B′(a)C(a)C(a)C′(a)∣∣=0
Also D′(x)=∣∣A′(x)A(a)A′(a)B′(x)B(a)B′(a)C′(x)C(a)C′(a)∣∣+∣∣A(x)0A′(a)B(x)0B′(a)C(x)0C′(a)∣∣ +∣∣A(x)A(a)0B(x)B(a)0C(x)C(a)0∣∣=∣∣A′(x)A(a)A′(a)B′(x)B(a)B′(a)C′(x)C(a)C′(a)∣∣
which clearly gives D' (a) = 0, since first and third row become identical.