If a ball is thrown vertically upwards with a velocity of 40 m/s. then velocity (in m/s) of the ball after two seconds will be (g= 10 m/s2)

Question

If a ball is thrown vertically upwards with a velocity of 40 m/s. then velocity (in m/s) of the ball after two seconds will be (g= 10 m/s2) (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Initial velocity (u) = 40 m/s Acceleration (a) = -g m/s2 = -10 m/s2 Time (t) = 2 seconds By 1st equation of motion, v = u + at v = 40 -10 (2) = 20 m/s

Q. If a ball is thrown vertically upwards with a velocity of $40 m / s$ . then velocity (in m/s) of the ball after two seconds will be ( $g = 10 m / s^{2})$

Initial velocity $(u) = 40 m / s$
Acceleration $(a) = - g m / s^{2} = - 10 m / s^{2}$
Time $(t) = 2$ seconds
By $1$ st equation of motion,
$v = u + a t$
$v = 40 - 10 (2) = 20 m / s$

Q. If a ball is thrown vertically upwards with a velocity of 40m/s. then velocity (in m/s) of the ball after two seconds will be (g=10m/s2)

Initial velocity (u)=40m/s Acceleration (a)=−gm/s2=−10m/s2 Time (t)=2 seconds By 1st equation of motion, v=u+at v=40−10(2)=20m/s

Q. If a ball is thrown vertically upwards with a velocity of $40 m / s$ . then velocity (in m/s) of the ball after two seconds will be ( $g = 10 m / s^{2})$

Initial velocity $(u) = 40 m / s$
Acceleration $(a) = - g m / s^{2} = - 10 m / s^{2}$
Time $(t) = 2$ seconds
By $1$ st equation of motion,
$v = u + a t$
$v = 40 - 10 (2) = 20 m / s$