Given a, b, c are in A.P. ∴2b=a+c ....(1)
Now , ∣∣x+1x+2x+3x+2x+3x+4x+ax+bx+c∣∣
[ Applying R2→2R2] =21∣∣x+12x+4x+3x+22x+6x+4x+a2x+2bx+c∣∣ =21∣∣x+12x+4x+3x+22x+6x+4x+a2x+(a+c)x+c∣∣
[using equation (1)] =21∣∣x+10x+3x+20x+4x+a0x+c∣∣
[Applying R2→R2−(R1+R3)] =21.0=0