Q.
If a,b,c are distinct non-zero complex numbers such that ∣a∣=∣b∣=∣c∣.
If az2+bz+c=0 and bz2+cz+a=0 have a root of modulus 1 , then the equation az2+bz+c=0 and bz2+cz+a=0
378
151
Complex Numbers and Quadratic Equations
Report Error
Solution:
az2+bz+c=0 and bz2+cz+a=0 have a root of modulus 1 z1+z2=a−b;z1z2=ac ∣z1∣∣z2∣=1 ∣z2∣=∣z1∣=1 ∣z1+z2∣=1 (z1+z2)(z11+z21)=1 (z1+z2)2=z1z2 b2=ac.....(i)
Similarly for 2nd equation c2=ab.....(ii)
from (i) and (ii) a3=b3=c3 ⇒a,b,c are z0,z0ω,z0ω2. ⇒ ratio of coefficients of two equations are same. ⇒ both roots are same.