Q.
If (a,b,c) & (a1,b1,c1) are two sets of non zero complex numbers satisfying Σa1a=0 and Σaa1=1−i then a2a12+b2b12+c2c12=?
1625
177
Complex Numbers and Quadratic Equations
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Solution:
Given, Σaa1=1−i aa1+bb1+cc1=1−i...(i)
and Σa1a=0 ⇒a1a+b1b+c1c=0
Now squaring (i) both sides we get a2a12+b2b12+c1c12=−2i−2(aba1b1+bcb1c1+acc1a1) =−2i−2abca1b1c1(c1c+a1a+b1b)=−2i