If a, b 0, then the minimum value of the expression ((1+a+a2)(1+b+b2)/a b) is equal to

Question

If a, b >0, then the minimum value of the expression ((1+a+a2)(1+b+b2)/a b) is equal to (A) 3 (B) 6 (C) 9 (D) 4

Tardigrade Admin · Accepted Answer

E=(a+(1/a)+1)(b+(1/b)+1) ≥ 9 ∴ E min =9 at a =1= b.

Q. If $a, b > 0$ , then the minimum value of the expression $\frac{( 1 + a + a ^{2} ) ( 1 + b + b ^{2} )}{ab}$ is equal to