Question

If $a,b>0$ and $\underset{0}{\overset{\infty }{\int }}\frac{\ln (bx)}{x^2+a^2}dx=\frac{\pi }{2a}$ then the value of $(ab)$ is

• A. 1
• B. $\frac{1}{e}$
• C. e
• D. $\frac{1}{2}$

Answer 1

Answer: (C)

Correct answer is (c) e