Question

If A and B are two events such that $P(A\cup B)=0.65$ and $P(A\cap B)=0.15$ , then $P(\bar{A})+P(\bar{B})=$

• A. 0.6
• B. 0.8
• C. 1.2
• D. 1.4

Answer 1

Answer: (C)

$P(A\cup B)+P(A\cap B)=P(A)+P(B)$
$P(\bar{A})+P(\bar{B})=2-[P(A\cup B)+P(A\cap B)]$